* @copyright 1997-2006 Allan Kent * @license http://www.opensource.org/licenses/bsd-license.php * BSD License * @version CVS: $Id$ * @link http://pear.php.net/package/Date * @since File available since Release 1.3 */ // }}} // {{{ Class: Date_Human /** * Class to convert date strings between Gregorian and Human calendar formats * * The Human Calendar format has been proposed by Scott Flansburg and can be * explained as follows: * The year is made up of 13 months * Each month has 28 days * Counting of months starts from 0 (zero) so the months will run from 0 to 12 * New Years day (00) is a monthless day * Note: Leap Years are not yet accounted for in the Human Calendar system * * @author Allan Kent * @copyright 1997-2005 Allan Kent * @license http://www.opensource.org/licenses/bsd-license.php * BSD License * @version Release: 1.4.7 * @link http://pear.php.net/package/Date * @since Class available since Release 1.3 */ class Date_Human { // {{{ gregorianToHuman() /** * Returns an associative array containing the converted date information * in 'Human Calendar' format. * * @param int day in DD format, default current local day * @param int month in MM format, default current local month * @param int year in CCYY format, default to current local year * * @access public * * @return associative array( * hdom, // Human Day Of Month, starting at 1 * hdow, // Human Day Of Week, starting at 1 * hwom, // Human Week of Month, starting at 1 * hwoy, // Human Week of Year, starting at 1 * hmoy, // Human Month of Year, starting at 0 * ) * * If the day is New Years Day, the function will return * "hdom" => 0 * "hdow" => 0 * "hwom" => 0 * "hwoy" => 0 * "hmoy" => -1 * Since 0 is a valid month number under the Human Calendar, I have left * the month as -1 for New Years Day. */ function gregorianToHuman($day=0, $month=0, $year=0) { /* * Check to see if any of the arguments are empty * If they are then populate the $dateinfo array * Then check to see which arguments are empty and fill * those with the current date info */ if ((empty($day) || (empty($month)) || empty($year))) { $dateinfo = getdate(time()); } if (empty($day)) { $day = $dateinfo["mday"]; } if (empty($month)) { $month = $dateinfo["mon"]; } if (empty($year)) { $year = $dateinfo["year"]; } /* * We need to know how many days into the year we are */ $dateinfo = getdate(mktime(0, 0, 0, $month, $day, $year)); $dayofyear = $dateinfo["yday"]; /* * Human Calendar starts at 0 for months and the first day of the year * is designated 00, so we need to start our day of the year at 0 for * these calculations. * Also, the day of the month is calculated with a modulus of 28. * Because a day is 28 days, the last day of the month would have a * remainder of 0 and not 28 as it should be. Decrementing $dayofyear * gets around this. */ $dayofyear--; /* * 28 days in a month... */ $humanMonthOfYear = floor($dayofyear / 28); /* * If we are in the first month then the day of the month is $dayofyear * else we need to find the modulus of 28. */ if ($humanMonthOfYear == 0) { $humanDayOfMonth = $dayofyear; } else { $humanDayOfMonth = ($dayofyear) % 28; } /* * Day of the week is modulus 7 */ $humanDayOfWeek = $dayofyear % 7; /* * We can now increment $dayofyear back to it's correct value for * the remainder of the calculations */ $dayofyear++; /* * $humanDayOfMonth needs to be incremented now - recall that we fudged * it a bit by decrementing $dayofyear earlier * Same goes for $humanDayOfWeek */ $humanDayOfMonth++; $humanDayOfWeek++; /* * Week of the month is day of the month divided by 7, rounded up * Same for week of the year, but use $dayofyear instead $humanDayOfMonth */ $humanWeekOfMonth = ceil($humanDayOfMonth / 7); $humanWeekOfYear = ceil($dayofyear / 7); /* * Return an associative array of the values */ return array( "hdom" => $humanDayOfMonth, "hdow" => $humanDayOfWeek, "hwom" => $humanWeekOfMonth, "hwoy" => $humanWeekOfYear, "hmoy" => $humanMonthOfYear ); } // }}} // {{{ humanToGregorian() /** * Returns unix timestamp for a given Human Calendar date * * @param int day in DD format * @param int month in MM format * @param int year in CCYY format, default to current local year * * @access public * * @return int unix timestamp of date */ function humanToGregorian($day, $month, $year=0) { /* * Check to see if the year has been passed through. * If not get current year */ if (empty($year)) { $dateinfo = getdate(time()); $year = $dateinfo["year"]; } /* * We need to get the day of the year that we are currently at so that * we can work out the Gregorian Month and day */ $DayOfYear = $month * 28; $DayOfYear += $day; /* * Human Calendar starts at 0, so we need to increment $DayOfYear * to take into account the day 00 */ $DayOfYear++; /* * the mktime() function will correctly calculate the date for out of * range values, so putting $DayOfYear instead of the day of the month * will work fine. */ $GregorianTimeStamp = mktime(0, 0, 0, 1, $DayOfYear, $year); return $GregorianTimeStamp; } // }}} } // }}} /* * Local variables: * mode: php * tab-width: 4 * c-basic-offset: 4 * c-hanging-comment-ender-p: nil * End: */ ?>